Heating and cooling with debris

The principle of operation discovered ghkbrew and described in this topical, let's consider an example of magma. If you pour magma of any temperature (even 0°C) on a pile of igneous rock, with a temperature of 1409°C, it will solidify with the temperature of the pile, i.e. 1049°C.

Next, this igneous rock needs to be heated by just a couple of degrees, to the state of liquid magma, and then repeat the process. In other words, we heat the resource by only a few degrees, but we get energy from the entire temperature difference. In this example it is the difference between 1409 ° C and 200 ° C (the temperature of the turbines).

Heating with debris


Here is a fairly compact scheme (as compact as possible) for obtaining energy. This trick works with any materials, not just magma. And even vice versa, it allows to cool materials down to 1°K.

The pump pumps alternately a portion of magma, with a temperature of about 1650°C and a portion of naphtha, a drop of which is cooled by a separate circuit. This technique allows the pump to heat slightly above the temperature of the naphtha, and it can even be made of copper (a steel pump was used for reassurance). The naphtha drips back under the pump every time it passes the elemental sensor on the tube.

Naphtha was chosen because it has the highest viscosity of the liquids available. There can be a 30 kg drop on the tile without flowing, unlike crude oil/petroleum at 0.3 kg or ethanol and all types of water at 0.03 kg.

Further the mechanics of the game is used, according to which there will be no change of the aggregate state of matter (e.g. crystallization of liquids into solid matter) if the liquid in the pipe is 1000 g or less. Further liquid magma will begin to cool, giving heat to steam, but will not turn into igneous rock and the pipe will not break.

The pipes under the turbines transfer the heat gradually, because they are made of different kinds of pipes, of different materials. And at the end, the cooled magma drips onto the igneous rock, takes its temperature and is discharged back into the magma lake.



Automatics, materials

 * Tube element sensor: naphtha
 * Timer: 9 green, 30 red period. Returns slightly less than it should (25%)
 * AT thermosensor: >85°C
 * Liquid valves: 1000 g/s
 * Tubes in chamber: up to second turbine - insulated, obsidian; white - igneous rock; yellow - radiator, copper; other tubes - granite, copper, igneous rock.

The temperature of the magma was about 1650°C. The steam temperature was between 197 and 207°C. If you have hotter magma (e.g. from a magma volcano), it would make sense to put 1 more turbine.

In principle, you can use a scheme without magma lake or volcano. You can heat the igneous rock to a liquid state in any way: glass forge, metal refinery (with liquid metal in the circuit), hydrogen engine, etc.

There is water in the cooling circuit. The efficiency of the circuit can be increased by using super coolant. At the same time it is possible to get rid of one AT.

Cooling with debris


Here is a scheme for cooling water, from 50...95°C to 5...8°C. The scheme uses the same principle as in the heating scheme: on strongly cooled ice (in the scheme -190°C), water drops, with a temperature at least slightly below 0°C. As a result, we get ice of the temperature that was lying in a pile.

The ice moving along the conveyor takes the heat from the hot radiator pipes, melts and is pumped out by the pump. The circuit operates with incoming water above 50°C. Lower water temperatures can cause the circuit to overcool and the water to freeze. This can either be avoided by using higher temperature ice (-50...-90°C) or by placing a liquid tepidizer at the bottom of the circuit.

Initially, such cold ice can be obtained using one of the oxygen or hydrogen cooling schemes.

Automatics, materials

 * Liquid valves: 1000 g/s
 * Timer: 1 green, 1.1 red, which is a little less than necessary (50%)
 * Tubes and tempshift plate behind conveyor loader: any (copper, granite, ceramic were used).
 * The auto-sweeper has a drop of petroleum.

Conclusions
Both schemes use a whole set of game exploits, which is acceptable. But as a result we have a gross violation of the laws of thermodynamics, clearly not intended by the developers.

So in the first scheme we get about 5800 W for free. The second scheme can be used for extreme cooling of anything up to solid oxygen.